-0.0006x^2+0.018+.33=0

Solution for -0.0006x^2+0.018+.33=0 equation:

-0.0006x^2+0.018+.33=0

We add all the numbers together, and all the variables

-0.0006x^2+0.348=0

a = -0.0006; b = 0; c = +0.348;
Δ = b2-4ac
Δ = 02-4·(-0.0006)·0.348
Δ = 0.0008352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.0008352}}{2*-0.0006}=\frac{0-\sqrt{0.0008352}}{-0.0012}
=-\frac{\sqrt{}}{-0.0012}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.0008352}}{2*-0.0006}=\frac{0+\sqrt{0.0008352}}{-0.0012}
=\frac{\sqrt{}}{-0.0012}
$